[Catalist] Catalist Digest, Vol 60, Issue 44

[Ray Redner]

I did up a quick punnett square, and it looks like you get the following
outcomes:

1/4 chance of XNXn (carrier female)
1/4 chance of XnXn (which is an affected female)
1/4 chance of XNY (normal male)
1/4 chance of XnY (affected male)

So there is a 50/50 chance that that particular pairing will result in a
child male or female that will be affected by that genetic trait.

Ray Redner

On 26 October 2017 at 09:52, <catalist-request at lists.stawa.net> wrote:

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>    1. Genetics question for Bio/ Human Bio Teachers (Greg Munyard)
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> Message: 1
> Date: Thu, 26 Oct 2017 01:51:32 +0000
> From: Greg Munyard <gmunyard at kennedy.wa.edu.au>
> To: "'catalist at lists.stawa.net'" <catalist at lists.stawa.net>
> Subject: [Catalist] Genetics question for Bio/ Human Bio Teachers
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> Good morning folks
>
> My colleagues and I are having some discussion around this question and I
> wondered if there is a consensus in the Bio/ Human Bio community on this:
>
> "If II-8 (XnY) and II-9 (XNXn) have more children, what is the probability
> that they will produce an affected daughter?" (Genotypes not in the
> original question - had to be ascertained from a pedigree.)
>
> One colleague's approach is to say that there is a 50% chance for
> producing a daughter and 50% chance that a daughter will be affected so the
> combination of these is a probability of 25%.
>
> My approach is to say that there is zero chance for sons to be daughters
> so that they represent a null sample. Considering only daughters then the
> chance of an affected daughter is 50%.
>
> Any guidance out there in the ether?
>
> Regards
>
> Greg Munyard
> Senior Teacher - Science
> [kennedy_email-footer-t4]
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-- 
*Ray Redner*
*Science Teacher*
*Carey Baptist College*
*"Don't doubt the creator, because it is inconceivable that accidents alone
could be the controller of this universe" Sir Isaac Newton*

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